(Use the density of water 62.4 lb/ft3.) Force. (Click on the graph for a larger version.) If the trough is full of water, find the force of the water on a triangular end. Let me know if you have any further questions. The trough in the figure below has width w2 ft, length L20 ft and height h4 ft. In this case, since the density is given in pounds (force), it is not necessary to use the g factor, so the formula is P = h x d. It is P = h x d x g where h is height in feet, d is density in mass per cubic feet, and g is the acceleration of gravity 32 ft/s 2. There is also a simple formula to get pressure at a particular depth. Since the density is given as pounds, we then divide the total weight of the water in pounds by the area of the bottom of the tank which is 100 x 100 = 10000 ft 2 to give a pressure ofĦ.24 x 10 7 lbs / 10000 ft 2 = 6.24 x 10 3 lbs / ft 2. There are 100 x 100 x 40 = 400000 ft 3 of the fluid in the tank, so the total weight of the fluid is 400000 x 156 = 6.24 x 10 7 lbs of fluid in the tank. The density of the fluid is 2.5 x 62.4 = 156 lbs / ft 3. When a person steps on the raft, it sinks 1.5 inches deeper into the water. (Use the density of water 62.4 lb/ft3.) Force Find the work to pump all of the water over the top of the trough. The basic water density at 4 degrees Celsius is equal to 62. The rounded value of 1 g/ml is what you'll most often see. Actually, the exact density of water is not really 1 g/ml, but rather a bit less (very, very little less), at 0.9998395 g/ml at 4.0 Celsius (39.2 Fahrenheit). If the trough is full of water, find the force of the water on a triangular end. So what is the value of water density in lb/ft3 at the freezing point It is equal to 62.421. A common unit of measurement for water's density is gram per milliliter (1 g/ml) or 1 gram per cubic centimeter (1 g/cm 3). Since the density of water is given as 62.4 lbs / ft 3. Since the specific weight of water is given as 62.4 lb/ft3 and we know that 1 gallon is equal to 1/7.48 cubic feet, we can substitute these values into the formula: Weight of 1 gallon of water 62.4 lb/ft3 x (1/7.48 ft3) Simplifying the equation: Weight of 1 gallon of water 62.4 lb/ft3 x 0.1337 ft3. The trough in the figure below has width w5 ft, length L16 ft and height h8 ft. Specific gravity refers to the density of a substance compared to the density of water.
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